The particular equivalence relationship between money and energy

Using the kilograms-meters-seconds system comporting with the price units in dollars per kilowatt-hour, the particular equivalence relationship between money and energy is emphasized in the postulated mechanism creating a vacuum against the barometric pressure of the impending atmosphere wherein A is the surface area of the opposing ram in square meter units, p_b is the presumed barometric pressure in Newton per square meters, and h is the stroke distance in meters, so that the potential energy difference from the initial position of the ram to its final stroke distance h is ΔE = (h)(A)(p_b) measured in joules. The thermal energy in the atmospheric volume is ΔE = (nR)T. Therefore for n moles of atmospheric gas and a gas constant R in energy per mole-degree Kelvin temperature T

(h)(A)(p_b) =Vp_b = (nR)T

Suppose that the relationship encountered in the Internet search is accurate at a given time so that $2.66x10^-5/ Newton-meter is the price paid i.e. therefore the value of the necessary total evacuated region of space (h)(A) is calculated as its volume times the impending external atmospheric pressure p_b times the price $2.66x10^-5)/ Newton-meter as the formula

  (((h)(A))(p_b)Newton-meters)(($2.66x10^-5)/Newton-meter)

= $(2.66x10^-5)((h)(A)(p_b)

The method of lifting the atmosphere is judiciously selected as that of placing the atmosphere onto a barge (pontoon) that is buoyed in tidal water that rises periodically. When the period of time is Δt within which the water reaches the paramount position h thereafter the average power potential derived is

(ΔE/Δt) watts = (((h)(A))(p_b)Newton-meters)/Δt.

At a repayment rate of a mere one million dollars per hour the total national debt cannot become paid in thirty years; for the total national debt of perhaps $800x10¹² how big must the evacuated region be for all transducers combined in order to pay off the debt in thirty years if the stroke velocity (the estimated rate of cumulative distance traveled by the rising tidal surface) is 4 meters per 24 hour period i.e. (4/24)(meters/hours) = h/Δt.

     Note that within analytical mechanics velocity times force is defined as the power (ΔE/Δt) in watts. The compelling unbalanced force is that of the impending pressure p_b applied over the buoyed ram horizontal plan section area A i.e. force = Ap_b. 
     Every penny saved is deemed a penny earned so that we can conclude that the energy from a non-fuel based transducer generated over the time span Δt is equivalent in monetary value to the money not spent in the payment for energy cost derived from combusted or otherwise depleted fuels.

Since ((h)(A)(p_b))joule $(2.66x10^-5/joule) = $800x10¹² total debt

then (H)(A) = $800x10¹²/$((2.66x10^-5)(p_b)) is the magnitude of the coefficient of the total necessary volume measured in cubic meters for the total volume of the evacuated displaced atmosphere. If this evacuated space is accrued constantly over the thirty years of a long term thirty year debentures issuance then only 30x(8 765.81277 hours) = 262974.3831 hours are available to accomplish the repayment of the debt. The debt prescriptively must become repaid at the end maturity date.

     There are 9.8 Newton per each 2.2 pounds; therefore there are 4.45 Newton/lbs so that an atmospheric pressure of p_b = 14.2 lbs per square inch is 63.254 Newton per each (2.54 x 10^-2)² squared meters

i.e. 63.254 Newton/(2.54 x 10^-2)² square meters

= 98044.742 Newton/(squared meters) = p_b(Newton)/(squared meters).

Thus multiplying 98044.742 Newton/(squared meters) by unity (using the meter

 divided by the meter) we derive the energy per unit volume

= 98044.742 Newton-meters /(cubic meters)

i.e. 98044.742 joules/(cubic meters). The price of a joule of energy, according to

 Internet research is $2.66x10^-5/ Newton-meters.

The resultant dollar value of one cubic meter of evacuated space is therefore

  ($2.66x10^-5/ Newton-meters)(98044.742 Newton-meters)/(cubic meters)

= $2.6079901372/(cubic meter). It is therefore obvious that the needed

meta-volume is derived as

($800x10¹²)/($2.6079901372/cubic meter)=

 (306,749,626,307,597.52552640903445822) cubic meter =

3.0674962630759752552640903445822x10¹⁴cubic meters.  

The tidal surface velocity (h/Δt)(meters/hour)=(4/24)(meters/hour) multiplied by the horizontal planar cross section area (A) of the pontoons is the displaced volume per unit time. Thus after thirty years the displacement is

(30x8 765.81277 hours)(A square meters)(4/24)(meters/hour)

= 3.0674962630759752552640903445822x10¹⁴cubic meters so that

(A)=(24/4)(30x(8 765.81277)square meters = 180x(8 765.81277)square meters

(A)= 1577846.2986 square meters throughout the thirty year period.

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